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Sunday, February 26, 2012

hw #8-1 thru 8-3

Fyi... we will be skipping the rest of Chapter 8 in the book (for now) and moving on to TRANSFORMATIONS...

Please know your 45-45-90 and 30-60-90 facts for Monday's FUN-FEST with Mrs. Bender! Man-o-man... I wish I was gonna be there!!

hw #8-1 pg 495-497 #1-12 ALL, 13-31 ODD

hw #8-2 pg 503-505 #1-12 ALL, 13-29 Odd

hw #8-3 pg 509-511 #1-13 ALL, 15-29 Odd

Of course, you should do the Mid-Chapter Quiz on pg 514 to your heart's content !!
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9 comments:

  1. AnonymousFebruary 26, 2012 at 5:13 PM

    I don't really understand questions like #8 on 8-3.. I looked at the example problem and I'm having trouble using the inverse of sine, etc. In the example Problem #3, how does the "sin" just disappear from one side and the inverse goes to the other side of the equation on A?

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    1. Mr. ChamberlainFebruary 26, 2012 at 6:32 PM

      Inverse Sine is found on your calculator as Sin^-1. The Inverse sine (or Cosine or Tangent) is simply the "inverse operation." The sine of a 30-degree angle is 1/2 or .5, SO, the inverse sine of .5 is 30-degrees.

      In other words...
      you can find the sine ratio (opp/hyp) of a given angle measure, OR
      you can find the measure of an angle for a given sine ratio. This latter technique is the inverse sine (or inverse trig ratio).

      Funky, eh?

      Delete
    2. AnonymousFebruary 26, 2012 at 8:36 PM

      Still kind of confused!!

      Delete
  2. AnonymousFebruary 26, 2012 at 5:18 PM

    I thought you said we would get to choose whether we were ready for the quiz on Wednesday or not?

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  3. AnonymousFebruary 26, 2012 at 5:39 PM

    I'm really having trouble on #17 and #19 in 8-3.. I'm trying to do "tangent" for them, so for example on #19 I write "(tan 25)=(10/x)" and multiply both sides by 1/10 and end up with "(tan 25)/10=x" but when I do this on the calculator it ends up a very small decimal.. Am I doing something wrong? I'm following the "TOA" rules!

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    1. AnonymousFebruary 26, 2012 at 5:47 PM

      Never mind about #17, I was supposed to use sin for it.. But I'm having the same problem with #21, whenever "x" ends up being on the denominator (because it is the hypotenuse) the answer turns out completely wrong and a very tiny decimal.

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  4. MC sweatpantsFebruary 28, 2012 at 9:28 PM

    I as well am confused about trigonometric equations. I don't understand what sin^-1 represents, or how it explains the length of another segment

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  5. AnonymousMarch 1, 2012 at 8:35 PM

    I'm confused on #8-4.. On #18. Whenever the x ends up being in the denominator, I have to multiply both sides by a fraction and that ends up dividing the tangent of the angle into a very tiny decimal.. Which is always wrong... Confused!!

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    1. AnonymousMarch 1, 2012 at 9:13 PM

      Can we do a problem like #33 on #8-4 in class tomorrow?

      Delete

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