1) 76 2) 48 3) 51 4) 68 5) 24 6) 5 7) 8 8) 7 9) w=104, x=22, y=108 10) a=30, b=42, c=80 d=116 11) w=105, x=75, y=210 12) a=140, b=70, c=47.5 13) 154 14) 120 15) Proof 1) (all of the GIVEN), 2) AF cong AG: cong. chords in a circle are equidistant from the center; 3) angl-AFG cong angl-AGF: isos triangles have cong base angles
16) answers will vary... basically premised on the fact that inscribed angles of congruent arcs are congruent 17) the two possibilities are 79 and 30 18) There should be 3 19) CE cong FE cong DE... tangent segments from outside a circle are congruent 20) The outside point, the point of tangency and the center of the circle are vertices of a right triangle. The tangent segment is a leg of that triangle, so it must be shorter than the distance from the outside point to the center, which is the hypotenuse of the right triangle.
I'm stuck on #14 on the MC Quiz.. I figured out the measure of the semicircle arc (1 step to finding arc AB) but cant seem to figure out the other arc..
I don't really understand #17.. Arcs PQ and QR are minor arcs, and according to the text so is arc PR, but I don't see how this is possible if PQ and QR only add up to 70, and there is only the possibility of 1 more arc to bring the measure of the circle up to 360..
Answers to Mid-Chapter Quiz
ReplyDelete1) 76
2) 48
3) 51
4) 68
5) 24
6) 5
7) 8
8) 7
9) w=104, x=22, y=108
10) a=30, b=42, c=80 d=116
11) w=105, x=75, y=210
12) a=140, b=70, c=47.5
13) 154
14) 120
15) Proof
1) (all of the GIVEN),
2) AF cong AG: cong. chords in a circle are equidistant from the center;
3) angl-AFG cong angl-AGF: isos triangles have cong base angles
16) answers will vary... basically premised on the fact that inscribed angles of congruent arcs are congruent
17) the two possibilities are 79 and 30
18) There should be 3
19) CE cong FE cong DE... tangent segments from outside a circle are congruent
20) The outside point, the point of tangency and the center of the circle are vertices of a right triangle. The tangent segment is a leg of that triangle, so it must be shorter than the distance from the outside point to the center, which is the hypotenuse of the right triangle.
GOOD LUCK!
Will we have bibles??
ReplyDeleteWait, is it not on 12-2?
ReplyDeleteWill there be proofs?
ReplyDeleteI'm not sure how to find x in #8 on the MC Quiz..
ReplyDeleteI'm also confused on how to find the value of w on #9 in the MidChap Quiz!
ReplyDeleteI'm stuck on #14 on the MC Quiz.. I figured out the measure of the semicircle arc (1 step to finding arc AB) but cant seem to figure out the other arc..
ReplyDeleteI don't really understand #17.. Arcs PQ and QR are minor arcs, and according to the text so is arc PR, but I don't see how this is possible if PQ and QR only add up to 70, and there is only the possibility of 1 more arc to bring the measure of the circle up to 360..
ReplyDeleteI have no idea what they even mean with "radii to each tangent" in #18..
ReplyDeleteNever mind, my dad helped me with most of the questions.. will we be allowed to use bibles, though?
ReplyDeleteWill we be able to use bibles? Sorry for asking so late.
ReplyDelete