Total Pageviews

Tuesday, January 10, 2012

hw#6-4 & 6-5

hw #6-4
#1-6 All
#9-15 Odd
#21,23
#28-37 All
#43,45

hw #6-5
#1-13 All
#17-23 Odd, 24

19 comments:

  1. Questions coming soon!

    ReplyDelete
  2. Soon meaning now (:

    ReplyDelete
  3. I'm confused on #1.. How can it be any of them when you don't have enough information? It does not have all equal sides (can't be a rhombus), does not have 4 right angles (can't be a rectangle), and does not have either mentioned before (can't be a square)..

    ReplyDelete
  4. Oh... NOW I understand.. Would it be because opposite angles of a parallelogram are congruent, so that makes the opposite angle congruent, and then it also makes the other 2 congruent because the rest of the measures equal 180 so they are also both 90.. :D ?

    So it is a square?

    ReplyDelete
  5. By "Given Property" for 28-37 does it mean what is given in the definition or what it CAN be? For example, for 32, a rhombus CAN have all right angles, but is not defined as having right angles..

    ReplyDelete
  6. You have to answer that for yourself... by the wording of the question, they are telling you that it is a parallelogram, so what must be true of the opposite sides? and the consecutive angles?

    ReplyDelete
  7. Wait, if a parallelogram's diagonals bisect eachother, and a square, rhombus and rectangle are all parallelograms, does that rule apply to them, too?

    (#34)

    ReplyDelete
  8. For 28-37... base your answer on what it MUST be, not what it CAN be... as you can see from the "odds" you should list every possibility

    ReplyDelete
  9. I'm waiting... ... ... ...

    Yes, list all quadrilaterals that apply

    ReplyDelete
  10. What are you waiting for?

    And does that mean that because a rhombus is a square, a square's diagonals also bisect its angles?

    ReplyDelete
  11. You can answer that for yourself, I think.

    You told me to wait.

    ReplyDelete
  12. For #43, I can figure out the variables on the picture without using the equation given for m<1.. Am I doing something wrong?

    ReplyDelete
  13. I'm confused on #10... Is it possible to answer "No"? Because it doesn't seem to give me any other clues..

    ReplyDelete
  14. Maybe it's because it's 8:44 and I'm blanking out but I can't seem to find what to do on #19 on #6-6.. And then question above was to #6-6, too.

    ReplyDelete
  15. WOOPS! I mean #6-5!

    ReplyDelete
  16. Can we go over #24 in #6-5 in class tomorrow? For some reason I feel like I can't think right now.. I've gotten to the point in my head where I've proved the interior pairs of triangles congruent (by SAS, although the center point was not named, which makes me suspicious..), but I don't know what to do next! Or if I'm right so far!

    ReplyDelete
  17. Sleep is a great teacher... take it from an expert... zzzzzzzzzzzz.

    c u 2mrw.

    ReplyDelete