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Saturday, October 22, 2011

hw #3-6 (constructions), 3-7, & 3-8 ALGEBRA!!!

...WHO SAYS that you can't go home again??
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13 comments:

  1. AnonymousOctober 22, 2011 at 4:23 PM

    I don't know how to find the slope of the x & y axes for #54 and #55! I'm pretty sure it's 0 but it doesn't seem right..

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  2. Mr. ChamberlainOctober 22, 2011 at 4:28 PM

    OMG... go back to algebra, do NOT pass go, do NOT collect $200!!

    You;ll recall that I said that you would get that wrong on the test... LAST NOVEMBER!!

    Slope is RISE OVER RUN... the 'change in y' over the 'change in x'

    The slope of a horizontal line is _____?
    The slope of a vertical line is ______?

    Which line, horizontal or vertical... results in a "divide by zero" situation?

    lmk if any bells are ringing!!!

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  3. AnonymousOctober 22, 2011 at 4:40 PM

    For #1 on pg 201, I got a slope of undefined for the slope of CD.. I got 1/0. Am I doing something wrong? I just substituted them into the slope formula..

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  4. AnonymousOctober 22, 2011 at 4:40 PM

    BELLS AREN'T RINGING! D:

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  5. AnonymousOctober 22, 2011 at 4:43 PM

    And I think I DID get it wrong on the test.. So nothing has changed!!

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  6. Mr. ChamberlainOctober 22, 2011 at 4:59 PM

    Dear Ding-a-lings!!

    Please go back to MathChamber Algebra Unit 5 section 1 and peruse the video tutor titles... if that doesn't 'jump start' you, I don't know what I can do!!!

    Do me a favor... for #1,2,3 on pg 201... plot the points (lines) on a graph AND calculate the slopes. Each problem is separate, are you trying to combine the A's and B's from all three problems? There are no vertical lines in the bunch, so a slope of 1/0 is not possible!!!

    OXYGEN!!!!

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  7. AnonymousOctober 23, 2011 at 3:16 PM

    Okay, watched the video tutors! And where it says "Write an equation for the y axis", do I just write "Undefined"?

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  8. Mr. ChamberlainOctober 23, 2011 at 3:33 PM

    nope... the SLOPE is undefined... there is an equation....

    Hint: What do all of the values of the x-coordinates of all of the ordered pairs that live on the y-axis have in common??

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  9. AnonymousOctober 23, 2011 at 4:18 PM

    I'm still not getting it..

    And for an equation of a line perpendicular to another, it only has to have the opposite reciprocal slope, but the y intercept does not matter, right?

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  10. AnonymousOctober 23, 2011 at 4:22 PM

    For #4 on pg 201, how am I supposed to find the y intercept of that line? I drew a graph but its not helping....

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  11. Mr. ChamberlainOctober 23, 2011 at 4:31 PM

    The equation for the y-axis is... x=0 !!

    There are many (infinite) lines prpndclr to a given line... so if you pick just one, the y-intercept will be random.

    =======================

    For #4, you know the slope of the line, since you were given the slope of a prpndclr line, right?

    So, in effect, they are giving you the SLOPE and a POINT! You can graph it OR you can solve algebraically using (ta-da!) POINT-SLOPE FORM!!

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  12. tyOctober 24, 2011 at 4:52 PM

    whats the online website called for the textbook

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  13. Mr. ChamberlainOctober 24, 2011 at 5:34 PM

    www.pearsonsuccessnet.com... NOT in your FAVORITES???? i'll post it on mathchamber.com

    ReplyDelete

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