If you focus on the formulas, you will be overloaded... focus on the concepts first and I think you will relax a bit... with the midpoint formula, you're just finding the middle/average of two numbers. With the distance formula, it's just the Pythagorean Thm on steroids.
DISCRIMINANT?! NAH!! You're over-thinking it. The distance formula takes the difference (positive or negative) of two numbers and SQUARES it. What happens when you SQUARE a number folks? Can the result be negative?? I don't think so... the SQUARING is what guarantees a positive result. HOO-RAY for Pythagoras (well, actually the ROPE-STRETCHERS... we know who did the REAL work!).
I'm finding a lot of this pretty simple (except that I have to keep checking back for the formulas), it's just algebra rollercoaster after you copy the formulas!
I'm confused.. For the example problem on pg 61, you have to simplify and multiply by pi.. but on the example problem on pg 62, you don't and just leave it there like a variable. Which do you do?
I'm stuck on #3 on pg 64?? The example only shows the method to use for the perimeter of a triangle in the coordinate plane, and I'm not sure it would be the same as a quadrilateral.. And, in the example, I'm not sure why they use the first method only twice when there are 3 points.. Please help!!
WOOPS :O I was doing #48 and solved all of the areas of the different sections and added them together & got the answer.. When I realized it said estimate..
Formula OVERLOAD!!
ReplyDeleteFor #4, (I'm just checking), would the answer be similar to the "Discriminant"? (I think that's what it's called!!)
ReplyDeleteIf you focus on the formulas, you will be overloaded... focus on the concepts first and I think you will relax a bit... with the midpoint formula, you're just finding the middle/average of two numbers. With the distance formula, it's just the Pythagorean Thm on steroids.
ReplyDeleteDISCRIMINANT?! NAH!! You're over-thinking it. The distance formula takes the difference (positive or negative) of two numbers and SQUARES it. What happens when you SQUARE a number folks? Can the result be negative?? I don't think so... the SQUARING is what guarantees a positive result. HOO-RAY for Pythagoras (well, actually the ROPE-STRETCHERS... we know who did the REAL work!).
I'm finding a lot of this pretty simple (except that I have to keep checking back for the formulas), it's just algebra rollercoaster after you copy the formulas!
ReplyDeleteCa-peesh! Thanks for the explanation, Mr.C.
ReplyDeleteI'm stuck on #57... I think it doesn't give enough info.. Wouldn't you need atleast 2 points' coordinates to find the 3rd? for each?
ReplyDeleteI'm stumped on #58 b. I know it somehow applies & changes my answer but I'm not sure how!!
ReplyDeleteHmmm... stuck on 57 and 58... THAT'S VERY GOOD NEWS.. I think I'll let that simmer overnight
ReplyDeleteQuestions for #1-8 coming tomorrow (if any!)
ReplyDeleteHmm.. Okay then, Mr.C!
ReplyDeleteAfter you use the formulas a few times... I think you will find that they actually make sense... which will make them much easier to memorize.
ReplyDelete@prettysimple above... sit back and enjoy the ride!
I'm confused.. For the example problem on pg 61, you have to simplify and multiply by pi.. but on the example problem on pg 62, you don't and just leave it there like a variable. Which do you do?
ReplyDeleteI'm stuck on #3 on pg 64??
ReplyDeleteThe example only shows the method to use for the perimeter of a triangle in the coordinate plane, and I'm not sure it would be the same as a quadrilateral.. And, in the example, I'm not sure why they use the first method only twice when there are 3 points.. Please help!!
What does "in terms of π (pi)" mean?
ReplyDeleteFor questions like #18-19 on pg 64, how do we know to convert to yards or feet?
ReplyDeleteI'm not sure where to start on #47 c. on pg 66!! I don't really know what "In terms of" means or how to convert the formula for perimeter to area!
ReplyDeleteWOOPS :O
ReplyDeleteI was doing #48 and solved all of the areas of the different sections and added them together & got the answer.. When I realized it said estimate..
Here is a simple example to demonstrate "in terms of π (pi)" :
ReplyDeleteUsing 3.14 for π , the circumference of a circle with a diameter of 10cm is 31.4cm.
Using π for π (i.e. "in terms of π), the circumference of the same circle is 10π cm.
I understand why you are saying the π looks like a variable... it is NOT. π is π or 3.14 or 3.14159 or 22/7... it is a VALUE, not a variable.
As you move on up through higher mathematics, you will often be asked to answer "in terms of π."
May the force be with you!
Keep the questions coming... I would love to see someone answer them... where's our team spirit?
ReplyDeleteTomorrow will basically be a review day for Tuesday's test. I will use your questions as a springboard for some smartboards!
Good night!
Will there be a topic for questions?
ReplyDelete