Dear Rope-Stretchers... MathChamber has been updated with video tutors and on-line quizzes for Unit 1... feel free to take a peek ahead... it can only help.
I don't understand #61 part b. If the lines are coplanar, then one plane would contain both lines. But if they're not, then no plane will. Can that be a solid answer?
To JUST PLANE CRAZY in 61b... you've got to see Mrs. Henke... remember the indefinite article "a" vs. the definite article "the"... two intersecting lines are ALWAYS coplanar to "a" single distinct plane, somewhere, somehow. Try it in space with two pencils (or drumsticks). However you position two lines, no matter how crazy the diagonals, they ALWAYS lie in "a" single plane. VISUALIZE, BABY, VISUALIZE!!
This is basic probability, otherwise known as the FUNDAMENTAL COUNTING PRINCIPAL (FCP). Because you are such BRILLIANT math students, you have skipped a few lessons along the way... but not to worry, you'll catch on fast.
Copy-and-paste this url into your browser: http://www.pearsonsuccessnet.com/content/HVT_English/academy123_content/wl-book-demo/ph-120s.html
Watch the video above and then read on:
In #62, you are given a choice of four points, from which you will pick two at random. When you pick the first point, you have four choices, yes? When you pick the second point, you only have three choices, since (based on the wording of the problem) you cannot pick the same point twice. You could draw a tree diagram to see all of the twelve possibilities, or (per the FCP) you can just multiply 4x3. If you want to see the "dirty detail." Of course, to answer this question, it was even simpler... ANYTIME you pick ANY two points in space, they are always collinear because you can always draw a (there's that indefinite article AGAIN... see sometimes Language Arts is important, too... go figure!) line through them.
In #63-64, you are asked to choose three points at random... four choices for the 1st point, three choices for the second point and two choices for the third point... FCP says 4x3x2=24, yes? Go ahead and list them all out... you'll find that 75% of the outcomes contain point D, thus making the outcome non-collinear, so the answer is 25% (or 1/4).
(N.B. you really didn't have to list every outcome... you could have used logic to figure out how many outcomes either included or excluded point D... can you tell me how??)
For #63, it's even simpler... we know that ANY three points in space are coplanar (remember the camera tripod), so we really don't have any math to do (perish the thought!)... the answer is clearly 100% (or 1).
You will be prompted to login when you click on a video tutor. Otherwise, you can use MathChamber.com without a login/password... FREE MATH FOR EVERYONE!!
To access the all of the online features, you can visit www.pearsonsuccessnet.com, but since the textbook is new, not everything is ready just yet.
I COMPLETELY agree!
ReplyDeleteDear Rope-Stretchers... MathChamber has been updated with video tutors and on-line quizzes for Unit 1... feel free to take a peek ahead... it can only help.
ReplyDeleteThanks Mista C!
ReplyDeleteI guarantee I will have SOME questions.. As usual
This homework is actuallu fun for a change! :)
ReplyDeleteI don't understand #61 part b. If the lines are coplanar, then one plane would contain both lines. But if they're not, then no plane will. Can that be a solid answer?
ReplyDeleteI really don't understand the concept of #62-64. How does probability tie into this and what am I supposed to do?
ReplyDeleteFun for a CHANGE??!! Doth my eyes deceive me??!!
ReplyDeleteTo JUST PLANE CRAZY in 61b... you've got to see Mrs. Henke... remember the indefinite article "a" vs. the definite article "the"... two intersecting lines are ALWAYS coplanar to "a" single distinct plane, somewhere, somehow. Try it in space with two pencils (or drumsticks). However you position two lines, no matter how crazy the diagonals, they ALWAYS lie in "a" single plane. VISUALIZE, BABY, VISUALIZE!!
This is basic probability, otherwise known as the FUNDAMENTAL COUNTING PRINCIPAL (FCP). Because you are such BRILLIANT math students, you have skipped a few lessons along the way... but not to worry, you'll catch on fast.
ReplyDeleteCopy-and-paste this url into your browser:
http://www.pearsonsuccessnet.com/content/HVT_English/academy123_content/wl-book-demo/ph-120s.html
Watch the video above and then read on:
In #62, you are given a choice of four points, from which you will pick two at random. When you pick the first point, you have four choices, yes? When you pick the second point, you only have three choices, since (based on the wording of the problem) you cannot pick the same point twice. You could draw a tree diagram to see all of the twelve possibilities, or (per the FCP) you can just multiply 4x3. If you want to see the "dirty detail." Of course, to answer this question, it was even simpler... ANYTIME you pick ANY two points in space, they are always collinear because you can always draw a (there's that indefinite article AGAIN... see sometimes Language Arts is important, too... go figure!) line through them.
In #63-64, you are asked to choose three points at random... four choices for the 1st point, three choices for the second point and two choices for the third point... FCP says 4x3x2=24, yes? Go ahead and list them all out... you'll find that 75% of the outcomes contain point D, thus making the outcome non-collinear, so the answer is 25% (or 1/4).
(N.B. you really didn't have to list every outcome... you could have used logic to figure out how many outcomes either included or excluded point D... can you tell me how??)
For #63, it's even simpler... we know that ANY three points in space are coplanar (remember the camera tripod), so we really don't have any math to do (perish the thought!)... the answer is clearly 100% (or 1).
Ca-peesh?
my login info is not working for the viedo toutors
ReplyDeleteI was able to access the VT's using "ryancu" and password "123456"... please try again... hmmm... did u forget the 'u'?
ReplyDeleteNote to everyone... pls change your passwords at the first opportunity... thanks!
I'm completely blanking out right now. Where am I supposed to go to login?
ReplyDeleteYou will be prompted to login when you click on a video tutor. Otherwise, you can use MathChamber.com without a login/password... FREE MATH FOR EVERYONE!!
ReplyDeleteTo access the all of the online features, you can visit www.pearsonsuccessnet.com, but since the textbook is new, not everything is ready just yet.
Kinda..
ReplyDeleteCould you explain #62-64 in class tomorrow? I sort of understand it now, but I think a better demonstration tomorrow would make it better!
ReplyDeleteFor you, anonymous... ANYTHING!
ReplyDelete